Bus.connectSyncMessage

Connect to SyncMessage signal.

A message has been posted on the bus. This signal is emitted from the thread that posted the message so one has to be careful with locking.

This signal will not be emitted by default, you have to call gst.bus.Bus.enableSyncMessageEmission before.

class Bus
ulong
connectSyncMessage
(
T
)
(
string detail = null
,,
Flag!"After" after = No.After
)
if (
isCallable!T &&
is(ReturnType!T == void)
&&
(
Parameters!T.length < 1 ||
(
ParameterStorageClassTuple!T[0] == ParameterStorageClass.none &&
is(Parameters!T[0] == gst.message.Message)
)
)
&&
(
Parameters!T.length < 2 ||
(
ParameterStorageClassTuple!T[1] == ParameterStorageClass.none &&
is(Parameters!T[1] : gst.bus.Bus)
)
)
&&
Parameters!T.length < 3
)

Parameters

detail string

Signal detail or null (default)

callback T

signal callback delegate or function to connect

void callback(gst.message.Message message, gst.bus.Bus bus)

message the message that has been posted synchronously (optional)

bus the instance the signal is connected to (optional)

after Flag!"After"

Yes.After to execute callback after default handler, No.After to execute before (default)

Return Value

Type: ulong

Signal ID